
One Newton step from any root-n start to asymptotic efficiency
Source:R/horowitz_native8.R
morie_one_step_efficient.Rd\(\tilde b_n = \tilde b_n^{*} - [\partial^2 S_n/\partial \tilde b\partial\tilde b']^{-1}\partial S_n/\partial\tilde b\) (2.52), where \(S_n\) is the weighted-NLS objective with \(W = 1/s_n^2\) and \(\tilde b_n^{*}\) is ANY root-n consistent estimator. The result attains \(\Omega_{SI}\).
Value
list: beta, beta_initial, step, omega, se, attains_omega_SI, theory_requires_steps, n_steps, bandwidth, n, d, method.
Details
The word doing the work is one. This is not an iterative
optimiser stopped early: (2.53)-(2.55) show the single step
already removes the leading term, so iterating to convergence buys
nothing asymptotically. That matters practically, because the
direct estimators of Sec. 2.6.1-2.6.3 are fast while minimising
\(S_n\) is slow and possibly multimodal – a cheap direct start
plus one step beats a full optimisation. Mirrors
morie.fn.hrzasym.