\(T_n(y) = \arg\max_{t}\ [n(n-1)]^{-1}\sum_i\sum_{j \ne i} (d_{iy} - d_{jy_0}) 1\{X_i'b_n - X_j'b_n \ge t\}\) (6.67), with \(d_{iy} = 1\{Y_i \ge y\}\).
Usage
morie_chen_transform(
x,
y,
bandwidth = NULL,
beta_hat = NULL,
y0 = NULL,
y_grid = NULL,
t_grid = NULL
)Arguments
- x
numeric matrix of covariates.
- y
numeric response.
- bandwidth
ignored; (6.67) uses no kernel.
- beta_hat
beta, rescaled to |b_1| = 1; first canonical direction when NULL.
- y0
location-normalisation point; median of y when NULL.
- y_grid
points at which to return T_hat.
- t_grid
the compact interval M searched over.
Value
list: y_grid, T_hat, objective_max, y0, beta, t_grid, uses_kernel, rate_exponent, faster_than_horowitz, normalisation, n, d, method.
Details
The construction rests on a sign, not a smoothing: \(E(d_{iy} - d_{jy_0} | X_i, X_j) \ge 0\) exactly when \(X_i'\beta - X_j'\beta \ge T(y)\), so maximising a pairwise sum over t locates \(T(y)\). It is a U-statistic of order two – hence the \(n(n-1)\) normalisation, and hence the quadratic cost.
This is not faster than Horowitz's estimator. Both are
\(n^{-1/2}\) (Theorem 6.6). The book compares them and finds
neither dominates: Horowitz's has smaller mean-square error near
the centre of the range of y, Chen's further out, and no known
estimator is efficient uniformly over y. bandwidth is
accepted for interface symmetry and NOT used – (6.67) contains no
kernel. Mirrors morie.fn.hrzchet.
