$$k(x,y) = \exp(-\|x-y\|^2/(2\sigma^2))$$ This takes the bandwidth, not the rate; the equivalent \(\gamma = 1/(2\sigma^2)\) is returned so the two conventions cannot be confused.
$$k(x,y) = \exp(-\|x-y\|^2/(2\sigma^2))$$ This takes the bandwidth, not the rate; the equivalent \(\gamma = 1/(2\sigma^2)\) is returned so the two conventions cannot be confused.