Fair-coin Heads-count pmf

P(k Heads in n fair flips) = C(n,k)/2^n.

Usage

CoinPmf(k, n)

Arguments

k

heads, >= 0.

n

flips, >= 0.

Value

list(k, n, probability).

References

Morin, D. J. (2016). Probability: For the Enthusiastic Beginner. Createspace. Eq (4.8).

Examples

CoinPmf(2, 4)$probability
#> [1] 0.375